% <PLAINTEXT>
% $BNL;RJ*M}3X(B $B!'(B $B1i=,LdBj(B 7-3 $B2rEz(B
% $B:n(B  $B@.(B  $B<T(B $B!'(B f9311196 $B?e8M(B $BOB9,(B
% $B:n@.G/7nF|(B $B!'(B /96/02/21
% $BEE;R%a!<%k(B $B!'(B f11196@ced.cas.uec.ac.jp
%
\mondai
{f9311196 $B?e8M(B $BOB9,(B}
{96/02/21}
{f11196@ced.cas.uec.ac.jp}
{7-3}
{
%----$BLdBjJ8(B----%
$B#1<!85>cJI(B $ (7.1) $ $B$G!"(B$ a = 1 $ $ {\rm \AA} $ $B!"(B  $ V_{0} = 1 {\rm eV} $ 
$B$N>l9g!"F~<MEE;R$N%(%M%k%.!<$,(B $ E = 0.5 $ $ {\rm eV} $ $B$N$H$-$N(B
$BF)2a3NN((B $ T $ $B$NCM$r5a$a$h!#(B\\
}
{
%----$B2rEzJ8(B---%
\begin{equation}
\begin{array}{lcl} 
 \displaystyle \alpha 
& = & \displaystyle \frac{2ma^{2}V_{0}}{\hbar^{2}} \\
& = & \displaystyle \frac{2 \times 9.11 \times 10^{-31} 
      \times (10^{-10})^{2} \times 1.60 \times 10^{-19} }
      { (6.63 \times 10^{-34}/2 \times 3.14)^{2} } \\
& = & \displaystyle 0.262
\end{array}
\end{equation}
\begin{equation}
 \displaystyle  x = \frac{E}{V_{0}} = \frac{0.5}{1} =  0.5
\end{equation}
$B$G$"$k$+$i!"(B$ E < V_{0} $ $B$N$H$-$NF)2a3NN((B $ T $ $B$O!"(B
\begin{equation}
\begin{array}{lcl}
 \displaystyle T 
& = & \displaystyle \frac{4x(1-x)}{\sinh^{2} \sqrt{\alpha(1-x)}+ 4x(1-x)} \\
& = & \displaystyle \frac{4 \times 0.5 \times (1-0.5)}
      {\sinh^{2} \sqrt{0.262 \times (1-0.5)} + 4 \times 0.5 \times (1-0.5)} \\
& = & \displaystyle 0.88
\end{array}
\end{equation}
$B$H$J$k!#(B
}
 
