The `b F` (`calc-fin-fv`

) [`fv`

] command computes
the future value of an investment. It takes three arguments
from the stack: ``fv( rate, n, payment)'`.
If you give payments of

The `I b F` [`fvb`

] command does the same computation,
but assuming your payments are at the beginning of each interval.
Suppose you plan to deposit $1000 per year in a savings account
earning 5.4% interest, starting right now. How much will be
in the account after five years? `fvb(5.4%, 5, 1000) = 5870.73`

.
Thus you will have earned $870 worth of interest over the years.
Using the stack, this calculation would have been
`5.4 M-% 5 RET 1000 I b F`. Note that the rate is expressed
as a number between 0 and 1, *not* as a percentage.

The `H b F` [`fvl`

] command computes the future value
of an initial lump sum investment. Suppose you could deposit
those five thousand dollars in the bank right now; how much would
they be worth in five years? `fvl(5.4%, 5, 5000) = 6503.89`

.

The algebraic functions `fv`

and `fvb`

accept an optional
fourth argument, which is used as an initial lump sum in the sense
of `fvl`

. In other words, `fv(`

.
`rate`, `n`,
`payment`, `initial`) = fv(`rate`, `n`, `payment`)
+ fvl(`rate`, `n`, `initial`)

To illustrate the relationships between these functions, we could
do the `fvb`

calculation "by hand" using `fvl`

. The
final balance will be the sum of the contributions of our five
deposits at various times. The first deposit earns interest for
five years: `fvl(5.4%, 5, 1000) = 1300.78`

. The second
deposit only earns interest for four years: ```
fvl(5.4%, 4, 1000) =
1234.13
```

. And so on down to the last deposit, which earns one
year's interest: `fvl(5.4%, 1, 1000) = 1054.00`

. The sum of
these five values is, sure enough, $5870.73, just as was computed
by `fvb`

directly.

What does `fv(5.4%, 5, 1000) = 5569.96`

mean? The payments
are now at the ends of the periods. The end of one year is the same
as the beginning of the next, so what this really means is that we've
lost the payment at year zero (which contributed $1300.78), but we're
now counting the payment at year five (which, since it didn't have
a chance to earn interest, counts as $1000). Indeed, 5569.96 =
5870.73 - 1300.78 + 1000 (give or take a bit of roundoff error).

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