Let's suppose it's January 14, 1991. The easiest thing to do is to keep trying 13ths of months until Calc reports a Friday. We can do this by manually entering dates, or by using t I:
1: <Wed Feb 13, 1991> 1: <Wed Mar 13, 1991> 1: <Sat Apr 13, 1991> . . . ' <2/13> RET DEL ' <3/13> RET t I
(Calc assumes the current year if you don't say otherwise.)
This is getting tedious--we can keep advancing the date by typing t I over and over again, but let's automate the job by using vector mapping. The t I command actually takes a second "how-many-months" argument, which defaults to one. This argument is exactly what we want to map over:
2: <Sat Apr 13, 1991> 1: [<Mon May 13, 1991>, <Thu Jun 13, 1991>, 1: [1, 2, 3, 4, 5, 6] <Sat Jul 13, 1991>, <Tue Aug 13, 1991>, . <Fri Sep 13, 1991>, <Sun Oct 13, 1991>] . v x 6 RET V M t I
1: 242 . ' <sep 13> - <jan 14> RET
And the answer to our original question: 242 days to go.